• hddsx@lemmy.ca
    link
    fedilink
    English
    arrow-up
    5
    ·
    6 months ago

    No. F=GMm/d2. The mass of the earth doesn’t change so g=GM/d2 will not change

    • Tar_Alcaran@sh.itjust.works
      link
      fedilink
      English
      arrow-up
      8
      ·
      6 months ago

      Ah but the earth doesn’t just attract the ball or feather. The bowling ball attracts the earth as well, and since it has more mass, it will pull the earth towards it faster than the feather.

      But if you drop them at the same time, that’s moot.

      • hddsx@lemmy.ca
        link
        fedilink
        English
        arrow-up
        3
        ·
        6 months ago

        In other words, the feather and ball are both attracted to the earth at the same rate but because the ball has a higher mass, the earth is very slightly more attracted to the ball

    • JohnDClay@sh.itjust.works
      link
      fedilink
      English
      arrow-up
      6
      ·
      6 months ago

      So why does the bowling ball fall faster in a vacuum? Does it appear faster locally because the heavier object makes local time slower than the lighter object compared to a distant observer? I’m trying to understand what the meme is getting at.

      • dev_null@lemmy.ml
        link
        fedilink
        English
        arrow-up
        2
        ·
        6 months ago

        Because it, ever so slightly, pulls Earth towards it with it’s own, miniscule gravity.

        • JohnDClay@sh.itjust.works
          link
          fedilink
          English
          arrow-up
          3
          ·
          6 months ago

          But that doesn’t make the bowling ball fall faster to a distant observer, just the earth fall twords the ball. To an observer on earth it would appear to fall faster though.